48k^2=12

Solution for 48k^2=12 equation:

48k^2=12

We move all terms to the left:

48k^2-(12)=0

a = 48; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·48·(-12)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*48}=\frac{-48}{96}
=-1/2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*48}=\frac{48}{96}
=1/2
$